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1012 Implement and test the following member function for the string class: void remove(unsigned n, unsigned k=O); This removes n characters from the object, beginning with character buf [ k] For example, String x("ABCDEFGHIJKL"); xremove(3, 5); would remove the substring I FGH I from the object X, changing it to " ABCDEI JKL I' lo13 Implement and test the following member function for the String class: void insert(const String& s, unsigned k=O); This inserts the string s into the current object, beginning with character buf [ k] For example, String x("ABCDEFGHIJKL"); String y("XYZ"); xinsert(y, 5); would insert I XYZ I into the object X, changing it to " ABCDEXYZFGHI JKL II Note that the third constructor would be invoked automatically to produce the same effect from the call: xinsert("XYZ", 5); Also note that x insert (y> prepends y to x, and that x.

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(7.37)

insert (y, x n ( > > is equivalent to x + = y, appending y to X 1014 Implement and test the following member function for the String class: void replace(const String& s, unsigned n, unsigned k=O); This replaces n characters from the object, beginning with character buf [k] with string S: String x("ABCDEFGHIJKL"); String y("XYZ"); xreplace(y, 6, 5); would replace the substring " FGHI JK " in the object x with the string s, changing x to "ABCDEXYZL" Note that the third constructor would be invoked automatically to produce the same effect from the call: xreplace("XYz", 6, 5); Also note that x replace ( y , m, n > ; is equivalent to xremove(6, 5); xinsert("XYZ", 5); 10.

Fig. 7-69

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15 Implement and test the following member function for the String class: int lastLocation(const String& s, unsigned k=O); This searches the object s buffer, beginning with character buf [k] for the string S If s is found to be a substring, then the index of its last occurrence is returned; otherwise -1 is returned For example, String x("ABCDEFGHIJKLABCDEFGHIJKL"); String y("FGH"); tout << xlastLocation(y) << endl; tout << xlastLocation(y, 20) << endl; String z("FGZ"); tout << xlastLocation(z) << endl; would print 17, -1, and -1 (See Problem 107).

7.60. The radius of a circle is 15. Find (a) the distance from its center to a chord whose length is 18; (b) the length of a chord whose distance from its center is 9. (7.38) 7.61. In a circle, a chord whose length is 16 is at a distance of 6 from the center. Find the length of a chord whose distance from the center is 8. (7.38) 7.62. Two externally tangent circles have radii of 25 and 9. Find the length of a common external tangent. (7.38)

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each die. (Remember that each reference to Rnd will return a different random value.) The strategy fits very naturally into the Visual Basic function procedure ThrowDice presented below.

7.63. In a 30 -60 -90 triangle, find the lengths of (a) the legs if the hypotenuse has length 20; (b) the other leg and hypotenuse if the leg opposite 30 has length 7; (c) the other leg and hypotenuse if the leg opposite 60 has length (7.39) 5 23. 7.64. In an equilateral triangle, find the length of the altitude if the side has length (a) 22; (b) 2a. Find the side if the altitude has length (c) 24 23; (d) 24. (7.39) 7.65. In a rhombus which has an angle measuring 60 , find the lengths of (a) the diagonals if a side has length 25; (b) the side and larger diagonal if the smaller diagonal has length 35. (7.39)

10.16 Implement and test the following member function for the String class: int location(const String& s, unsigned n=O, unsigned k=O); This searches the object s buffer, beginning with character buf [ k] for the string S. If s is found to be a substring, then the index of its (n+l)st occurrence is returned (in other words, the first n occurrences of the string s are ignored); otherwise -1 is returned. For example, String x("ABCDEFGHIJKLABCDEFGHIJKLABCDEFGHIJKLABCDEFGHIJKL~); String y("FGH"); tout << x.location(y) tout << x.location(y, tout << x.location(y, tout << x.location(y, tout << x.location(y, << endl; 0, 20) -X endl; 2) << endl; 2, 20) << endl; 4) << endl;

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