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Notice that the declarations and procedure definitions within Module1 are all Public, so that they can be accessed within both Form1 and Form2. Also, note that the references to the various procedures are written somewhat differently in this version of the code, since the procedure definitions and the procedure references are contained in different modules. Fig. 7.20 shows the opening dialog box when the program is executed. Clicking on New Game will result in another dialog box, similar to that shown in Fig. 7.21. (Fig. 7.21 shows the dialog box that results from winning on the first throw. Other dialog boxes are similar.) Note that the only choice shown in Fig. 7.21 is to return to the opening dialog box, since this particular game has ended with a win. Also, note that the last roll (i.e., the roll following the first roll) box is disabled, since this particular game required only one roll of the dice.

Fig. 8-4

But the members of Y have the same signatures as those in X. So Y'S member function f ( ) the f ( ) defined in X, and Y'S data member a dominates the a defined in X.

The trigonometric ratios for 30 and 60 may be obtained by using a 30 -60 -90 triangle (Fig. 8-4); in such a triangle, the ratio of the sides is a:b:c 1: 23:2. Thus: (a) tan 30 (b) sin 30 (c) cos 30 1 23 1 0.500 2 23 2 1 # 23 23 23 23 3 0.577 (d) tan 60 (e) sin 60 (f) cos 60 23 1 23 2 1 2 1.732 0.866 0.500

Here is a test driver for the two classes:

x x;

Finding lengths of sides by trigonometric ratios In each triangle of Fig. 8-5, solve for x and y to the nearest integer.

x.a = 22; x-w; tout << 'x.a = ' c-c x.a CC endl; y y; y.a = 44; // assigns y.x: :a = 66; // assigns // invokes y.fO; y.X::f(); // invokes tout << I' y . a = I' C-K y.a CC endl; tout -C-C "y.X::a = ' C-C y.X::a << endl; x z = y; tout << '1z.a = cc z.a << endl;

Fig. 8-5

Here, y has access to two different data members named a and two different functions f ( ) . The defaults are the ones defined in the derived class Y. The scope resolution operator : : is used in the form x: : to override the defaults to access the corresponding members defined in the parent class X. When the x object z and initialized with y, its x members are used: z . a is assigned the value y.X::a. This diagram illustrates the three objects x, y, and z:

(a) Since tan 40 Since cos 40 (b) Since tan 50 Since sin 40 (c) Since sin 40 Since cos 40 x 150(0.8391) 126. , x 150 tan 40 150 150 150 150 196. y ,y 0.766 cos 40 x , x 150 tan 50 150(1.1918) 179. 150 150 150 150 233. y ,y 0.6428 sin 40 x , x 150 sin 40 150 (0.6428) 96. 150 y , y 150 cos 40 150(0.776) 115. 150

Example 11.6 and most of the remaining examples in this chapter are designed to illustrate the intricacies of inheritance. They are not intended to exemplify common programming practice. Instead, they focus on specific aspects of C++ which can then be applied to more general and practical situations. In particular, the method of dominating data members as illustrated in Example 11.6 is rather unusual. Although it is not uncommon to override function members, dominating data members of the same type is rare. More common would be the reuse of the same data name with a different type, like this:

CHAP. 7]

Solving trigonometry problems (a) An aviator flew 70 mi east from A to C. From C, he flew 100 mi north to B. Find the measure of the angle of the turn (to the nearest degree) that must be made at B to return to A. (b) A road is to be constructed so that it will rise 105 ft for each 1000 ft of horizontal distance. Find the measure of the angle of rise to the nearest degree, and the length of road to the nearest foot for each 1000 ft of horizontal distance.

CHAP. 1 l]